Answer:
Explanation:
Annual demand (D) = 20000 units
Number of days per year = 250
Demand rate(d) = D/number of days per year = 20000/250 = 80 units
Production rate(p) = 655 units
Set up cost(S) = $1800
Holding cost (H) = $1.50
A) Optimum run size(Q) = sqrt of {2DS / H [1-(d/p)]}
= sqrt of {(2x20000x1800) /1.50[1-(80/655)]}
= Sqrt of [7200000/1.50(1-0.1221) ]
= sqrt of [72000000/(1.50 x 0.8779)]
= sqrt of (7200000/1.31685)
= Sqrt of 5467593.1199
= 2338 units
b) Maximum inventory ( I - max) = (Q/p) (p-d) = (2338/655)(655-80) = 3.5695 x 575 = 2052.46 or rounded off to 2052 units
Average inventory = I-max/2 = 2052/2 = 1026 units
C) Number of production setups per year = D/Q = 20000/2338 = 8.55 or rounded up to 6
d) optimal length of production run = optimal run size /production rate = 2338/655 = 3.56 or rounded up to 4 days
Answer:
Explanation:
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Answer:
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