It takes 4.3 seconds for the rocket to return to earth.
The equation is:

where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

We will use the quadratic formula to solve this. The quadratic formula is:

Plugging in our information we have:

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Answer:
X = 4, 3
Step-by-step explanation:
I don't know if that's what you were looking for
Answer:
The surface area of Triangular base Prism = 3682 cm²
Step-by-step explanation:
Given in question as :
For a Triangular base prism ,
The base of prism (b) = 24 cm
The height of prism (l) = 29 cm
Each side length (s) = 37 cm
The height of base triangle ( h ) = 35 cm
Hence , we know that The surface area of Triangular base prism is
= (b×h) + (2×l×s) + (l×b)
= (24×35) + (2×29×37) + (29×24)
= (840) + (2146) + (696)
= 3682 cm²
Hence The surface area of Triangular base Prism is 3682 cm² Answer