When solving an equation with an absolute value term, you make two separate equations ans solve for x:
Equation 1: |4x-3|-5 = 4
1st add 5 to both sides:
|4x-3| = 9
Remove the absolute value term and make two equations:
4x-3 = 9 and 4x - 3 = -9
Solving for x you get X = 3 and x = -1.5
When you replace x with those values in the original equation the statement is true so those are two solutions.
Do the same thing for equation 2:
|2x+3| +8 = 3
Subtract 8 from both sides:
|2x+3| = -5
Remove the absolute value term and make two equations:
2x +3 = -5
2x+3 = 5
Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.
The answer is:
C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
Answer: C. Industrialization
Step-by-step explanation:
60 is my resultados of area
Answer:
none of them
Step-by-step explanation:
Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.
line 1:
y – 1 = (x+2)
y = x + 3
slope of line 1 = 1
line 2:
y + 2 = –3(x – 4)
y + 2 =
-3*x + 12
y = -3*x + 10
slope of line 2 = -3
m1*m2 = 1*(-3
) = -3
They are not perpendicular
line 3:
y − 5 = 3(x + 11)
y − 5 = 3*x + 33
y = 3*x + 38
slope of line 3 = 3
m1*m3 = 1*3 = 3
They are not perpendicular
line 4:
y = -3x –
slope of line 4 = -3
m1*m4 = 1*(-3
) = -3
They are not perpendicular
line 5:
y = x – 2
slope of line 5 = 1
m1*m5 = 1*1 = 1
They are not perpendicular
line 6:
3x + y = 7
y = -3x + 7
slope of line 6 = -3
m1*m6 = 1*(-3
) = -3
They are not perpendicular
