Get y by itself:
4x-3y>equal to -9
-4x. -4x
-3y>equal to -4x-9
Divide by -3
y>equal to 4/3x+3
To graph, go to y=3 and plot (0,3). Then do slope. Up 4 and 3 right. Go down 4 and 3 left to get the other side of the inequality. This line will be solid. You shade upwards by the way.
I'm pretty sure the answer is c. hope this helps
The answer is the third one.
(7,0)
Answer:
Step-by-step explanation:
First simplify:
Therefore we have:
![\sum\limits_{n=1}^{150}[-1-(n-1)]=\sum\limits_{n=1}^{150}(-n)=(-1)+(-2)+(-3)+...+(-150)\\\\-1,\ -2,\ -3,\ -4,\ ...,\ -150-\text{it's the arithmetic sequence}\\\text{with the common difference d = -1.}\\\\\text{The formula of a sum of terms of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=150,\ a_1=-1,\ a_n=-150:\\\\S_{150}=\dfrac{-1+(-150)}{2}\cdot150=(-151)(75)=-11,325](https://tex.z-dn.net/?f=%5Csum%5Climits_%7Bn%3D1%7D%5E%7B150%7D%5B-1-%28n-1%29%5D%3D%5Csum%5Climits_%7Bn%3D1%7D%5E%7B150%7D%28-n%29%3D%28-1%29%2B%28-2%29%2B%28-3%29%2B...%2B%28-150%29%5C%5C%5C%5C-1%2C%5C%20-2%2C%5C%20-3%2C%5C%20-4%2C%5C%20...%2C%5C%20-150-%5Ctext%7Bit%27s%20the%20arithmetic%20sequence%7D%5C%5C%5Ctext%7Bwith%20the%20common%20difference%20d%20%3D%20-1.%7D%5C%5C%5C%5C%5Ctext%7BThe%20formula%20of%20a%20sum%20of%20terms%20of%20an%20arithmetic%20sequence%3A%7D%5C%5C%5C%5CS_n%3D%5Cdfrac%7Ba_1%2Ba_n%7D%7B2%7D%5Ccdot%20n%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20n%3D150%2C%5C%20a_1%3D-1%2C%5C%20a_n%3D-150%3A%5C%5C%5C%5CS_%7B150%7D%3D%5Cdfrac%7B-1%2B%28-150%29%7D%7B2%7D%5Ccdot150%3D%28-151%29%2875%29%3D-11%2C325)
Answer:
a P(x) = Q(x)
b. R(x) = Q(x)
c. R(x) = P(x)
d. Yes
Step-by-step explanation:
This is a statement of logical connectives.
a P(x) = Q(x)
b. R(x) = Q(x)
c. R(x) = P(x)
d. Yes, (c) follows from (a) and (b)
Reasoning:
(c) is equivalent to ∀x ¬ P(x) ∨ Q(x)
Proof:
Follow the tautology (X→Υ) Ξ(¬x∨Υ)
This gives X: R(x) ∧ ¬ P(X)
