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77julia77 [94]
3 years ago
11

You pull a Queen (any of 4 suits) out of 52-card deck. I pull a pair of grey socks from the 12 -pair pack. There are 3 pairs of

grey socks. What event has a smaller chance to happen?
Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer: The probability of pulling a Queen has a smaller chance of happening.

Step-by-step explanation: In a 52-card deck, you have 4 Queens altogether belonging to each of the four suits. If you pull a card at random out of a complete pack, the probability of picking a Queen would be as follows;

P(Q) = Number of required outcomes/Number of all possible outcomes

P(Q) = 4/52

P(Q) = 1/13

P(Q) = 0.07692 or 7.69%

Also in a 12-pair pack of socks, you have 3 pairs with the color grey. The probability of picking a pair of grey socks at random is given as follows;

P(G) = Number of required outcomes/Number of all possible outcomes

P(G) = 3/12

P(G) = 1/4

P(G) = 0.25 or 25%

Therefore the probability of pulling a Queen has a 7.69% chance of happening and thats a lower chance.

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Answer:

I believe it's false

Step-by-step explanation:

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3 years ago
Point K on the number line shows Kelvin's score after the first round of a quiz: A number line is shown from negative 10 to 0 to
Ierofanga [76]

Answer:

The correct option is;

3 + (-9) = -6, because -6 is 9 units to the left of 3

Step-by-step explanation:

The given information are;

Kelvin's score after the first round is shown at point K on the number line

The range of numbers on the number line = -10 to +10

The position of point K after the first round = +3

The number of points Kevin lost in the second round = 9 points

Therefore, Kevin's cumulative score = +3 - 9 = -6

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7 0
4 years ago
Please anybody help me in this
Simora [160]

Answer:

<h2>a) 0.38</h2><h2>b) 0.62</h2><h2>c) 0.78</h2><h2>d) 0.03</h2><h2>e) 0.02</h2><h2>f) 0.62</h2><h2>g) 0.38</h2>

Step-by-step explanation:

a)

Probability of a owner to be moved = \frac{total owner}{total Americans} = \frac{14.8}{39} = 0.379 ≅ 0.38

b)

Probability of a renter to be moved = \frac{total renters}{total Americans} = \frac{24.2}{39} = 0.62

c)

Probability of a person who moved in the same state = \frac{Persons who moved to the same state}{Total Americans} = \frac{30.4}{39} = 0.779 ≅ 0.78

d)

Probability of a person who moved to a different country = \frac{Total moved to different country}{Total Americans} = \frac{1.3}{39} = 0.033 ≅0.03

e)

Probability of a owner who moved to a different country = \frac{Owners that moved to different country}{Total people who moved to different country} = \frac{0.3}{14.8} = 0.02

f)

Probability of a renter moving in the same state = \frac{Renter that moved in the same state}{Total persons moved in the same state} = \frac{18.7}{30.4} = 0.615 ≅ 0.62

g)

Probability of an owner moved to different state = \frac{Owners moved in different state}{Total moved in different state} = \frac{2.8}{7.3} ≅0.38

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