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trasher [3.6K]
3 years ago
5

An acute angle ? is in a right triangle with cos ? = nine tenths. what is the value of sec ?? square root of nineteen divided by

nine square root of nineteen divided by ten nine divided by nineteen ten ninths
Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
What...................................numberxs
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What is the area of this composite shape?<br><br><br> Enter your answer in the box.<br><br> _in²
LuckyWell [14K]

The area of the composite figure is 40 in^2

Explanation:

From the given figure, we can see that the area of the composite figure = area of the rectangle + area of the triangle.

Area of the rectangle (A_1):

The formula is given by

A_1=length\times width

where length = 5 and width = 5

Substituting, we have,

A_1=7\times 5=35 in^{2}

Thus, the area of the rectangle = 35 i n^{2}

Area of the triangle (A_2):

The formula is given by

A_2=\frac{1}{2} bh

where b=5-3=2 i n

and h=12-7=5 \text { in }

Substituting, we have,

A_2=\frac{1}{2} (2)(5)\\A_2=5 in ^{2}

Thus, the area of the triangle = 5in ^{2}

Area of the composite figure = Area of the rectangle + area of the triangle

Area of the composite figure = 35 i n^{2}+5 i n^{2}=40 i n^{2}

Thus, the area of the composite figure is 40 in^2

3 0
2 years ago
What is the following quotient? 3 sqrt 60 / 3 sqrt 20
UkoKoshka [18]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
2 years ago
Jack mails 10 packages that each weigh the same amount. If the combined weigh of all 10 package is 67 1/2 pounds, how much does
kykrilka [37]
The answer is 6.75, I hope this helped

7 0
3 years ago
P = (12, 4) and M = (-8, 8)
Elena-2011 [213]
You can look on the app Socratic to help you.
3 0
2 years ago
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