Let the leading term of the polynomial, f(x), be axⁿ.
Examine the possibilities.
n a x -> - ∞ x -> +∞
------- ---- ----------- ------------
even a>0 f -> +∞ f -> +∞ Not true
even a<0 f-> - ∞ f-> -∞ True
odd a>0 f-> -∞ f-> +∞ Not true
odd a<0 f-> +∞ f-> -∞ Not true
Answer:
(a) the degree of the polynomial is even, and
(b) the coefficient of the leading term is negative.
Answer:
C.60
Step-by-step explanation:
4×12=48
18-12=6
6×2=12
48+12=60
When simplified the answer is -2n^3+13
I'm NOT 100% confident in my answers.
Graph 1:
Range: Option B
Graph 2:
Range: Option A
The range has to start at zero since that's the lowest point we can go, only one with zero is first option.
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Answer:
Step-by-step explanation:
The domain is the span of x-values covered by the graph.
From the graph, we can see that the x-values covered by the graph is all values to the left of zero including zero.
Therefore, the domain is all x-values less than or equal to 0:
Further notes:
In interval notation, this is:
![(-\infty,0]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C0%5D)
