<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
All students in each grade
audience: <u>students</u> - counts for both boys and girls.
option (B) for teachers is irrevelant.
option (C) doesn't include girls.
option (D) doesn't include the entire school
Hence, option A is correct.
Answer: 18x^3-9x^2+21x
Solution:
3x(6x^2-3x+7)=
Applying the distributive property in the multiplication to eliminate the parentheses:
(3x)(6x^2)+(3x)(-3x)+(3x)(7)=
(3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=
18x^3-9x^2+21x
Step two is the answer i hope that helps
