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atroni [7]
2 years ago
5

Amanda's parents invested $10,000 into a savings account for her college fund when she was born. The savings plan compounds inte

rest yearly at a rate of 3.75%. How much money will be in Amanda's college fund when she turns 18? Round your answer to the nearest cent.
A. $19,399.29
B. $19,149.68
C. $20,146.75
D. $20,652.19
Mathematics
1 answer:
Inessa05 [86]2 years ago
8 0

Answer:

A. $19.399.29

Step-by-step explanation:

to be honestly, i don't know how to do this in my head or if there is any formulae to that, every year when interest adds to principal it would makes the principal more and there would be a new amount of interest, but there is a compound interest calculator on internet, i typed the number in and it tells me the answer.

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C maybe bro I’m not really sure tho think I’m messing up

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3 years ago
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What are the first, second, and third frequencies audible from a 20 cm long organ pipe when (A) only one end is open and when (B
kotykmax [81]
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz

The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz


2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz


3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz


B) The answers are:

the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz

The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz


2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz


3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
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Vera_Pavlovna [14]

Answer:

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Give abc =jkl,m<b=55 and m<L=25 what is the measure of <j
Irina18 [472]

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3 years ago
3. Solve the inequality –2(z + 5) + 20 > 6.
12345 [234]

\boxed{-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z

<em><u>Solution:</u></em>

<em><u>Given inequality is:</u></em>

-2(z+5)+20>6

We have to solve the given inequality

-2\left(z+5\right)+20>6\\\\\mathrm{Subtract\:}20\mathrm{\:from\:both\:sides}\\\\-2\left(z+5\right)+20-20>6-20\\\\\mathrm{Simplify}\\\\-2\left(z+5\right)>-14

Multiply\ both\ sides\ by\ -1\ \left(reverse\:the\:inequality\right)

Whenever we multiply or divide an inequality by a negative number, we must flip the inequality sign

\left(-2\left(z+5\right)\right)\left(-1\right)

<em><u>Thus the solution to inequality is:</u></em>

-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z

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