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dybincka [34]
3 years ago
7

Help plz it’s algebra 2 vertex forms of quadratic function

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

I did the entire thing I attached the picture for it !! hope this helps !!

I didnt do 5 and 7 cause I forgot how to do those!!

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What is 3,108 rounded to the nearest thousand
goblinko [34]

Answer:

3100

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Pls help me I am stuck
Aleonysh [2.5K]
I think the answer is Sample 4. 

Hope this helps!
4 0
3 years ago
Find the size of each of 66 payments made at the end of each year into a 88​% rate sinking fund which produces ​$36000 at the en
Assoli18 [71]

Answer: $7787.99

Step-by-step explanation:

We know that the formula to find the periodic payment on an annuity is given by :-

P=\dfrac{r(PV)}{1-(1+r)^{-n}}, where PV is the present value , r is the rate of interest ( in decimal ) and n is the number of payments.

Given : Present value : $36000

Rate of interest = 8%=0.08

Time period = 6 years

Then , the periodic payment will be :-

P=\dfrac{(0.08)(36000)}{1-(1+0.08)^{-6}}\\\\\Rightarrow\ P=\dfrac{2880}{0.3698}\\\\\Rightarrow\ P=\$7787.99

Hence, the payment size is $7787.99.

8 0
3 years ago
3/9 + 3/27 = ? Adding fractions
RideAnS [48]
\frac{3}{9} + \frac{3}{27} equals \frac{4}{9}.

First, simplify \frac{3}{9} to \frac{1}{3} and also \frac{3}{27} to \frac{1}{9}. Your problem should look like: \frac{1}{3} + \frac{1}{9}.
Second, find the least common denominator of \frac{1}{3} and \frac{1}{9} to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: \frac{1x3}{3x3} + \frac{1}{9}.
Fourth, simplify to get the denominators the same. Your problem should look like: \frac{3}{9} + \frac{1}{9}.
Fifth, join the denominators. Your problem should look like: \frac{3+1}{9}.
Sixth, simplify. Your problem should look like: \frac{4}{9}, which is the answer.

4 0
3 years ago
In spherical geometry, all points are points on the surface of a sphere. A line is a circle on the sphere whose diameter is equa
mamaluj [8]

Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.

Step-by-step explanation:

For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.

in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.

Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.

Two triangles in sphere that are similar must be congruent.

8 0
3 years ago
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