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3 years ago

What is the range of f(x) = 3X + 9? {yly<9} {yly>9} {yly> 3} {yly<3}

Mathematics

1 answer:

4vir4ik [10]3 years ago

7 0

Answer:

the set of all real numbers

Step-by-step explanation:

f(x) = 3X + 9 is a polynomial, and so both the domain and the range are "the set of all real numbers."

None of your answer choices match this. Check with your teacher if you can.

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determine if each polygons are similar, if so, write the similarity statement and the similarity ratio. if not explain why.

Delicious77 [7]

Answer:

They are not similar

Step-by-step Explanation:

For two polygons to be considered similar, two conditions must be met:

1. The ratio of their corresponding sides must be equal, and must have the same scale factor.

2. Their corresponding angles must be the same. That is, the corresponding angles must be congruent.

Now let us examine the two polygons ( ∆AYP and ∆BOX) given to ascertain if they are similar.

First, we can observe that only two of their corresponding sides were given. The third corresponding side, "YP/OX" is not given. This makes it difficult for us to tell if the polygons are similar, if we are to base our conclusion on merely considering the ratio of their corresponding sides.

Although, the two given corresponding sides (AY/BO & AP/BX), both have equal ratio ⅖, i.e. AY/BO = AP/BX = ⅖. This is not enough to tell both polygons are similar, as we cannot tell if the third corresponding side would give us same ratio, since it wasn't given in the diagram.

==>Next is to examine the interior angles of the polygons, whether the measure of their corresponding angles are the same.

Thus, from the diagram, we can see that two angles of the each triangle were given. We can find the measure of the third angle not given since we know that sum of the interior angles of a triangle = 180°

Thus, <P in ∆AYP = 180 - (90+20) = 180 - 110

<P = 70°

Thus, <B in ∆BOX = 180 - (90+80) = 180 - 170

<B = 10°

From the above calculation, comparing both polygons having known the measures of their corresponding angles, we can conclude that both polygons given in the question are not similar.

This is because the measure of their corresponding angles are not congruent.

<A is not congruent to <B, so likewise with <P and <X.

4 0

3 years ago

A quadrilateral has angles

Liono4ka [1.6K]

Answer:

95 degrees

Step-by-step explanation:

The sum of the measures of a quadrilateral is 360 degrees. 360-105-80-80 = 95 degrees

4 0

2 years ago

Read 2 more answers

11. Given: TQ bisects ZRTP, QS || PT<br> RT = 30. Find QP, RS and QS

yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

<u>Explanation</u>:

Given that TQ bisects <RTP

$therefore$ (1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

$RQ/RP=RS/RT=QS/PT$ $9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm$

3 0

3 years ago

280 divided by 8 equal

IgorC [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

The Art and History Museum offers a family discount card for a donation of $57. I The table shows the price per person with and

Murljashka [212]

Answer:

8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

Step-by-step explanation:

Price without Discount Card Price with Discount Card

Ticket (12 & Under) $10 $8

Adult's Ticket $15 $12

Let x be the number of visits

Price without discount card for 2 adults and 1 child ticket

Price without discount for x visits = $x(15 \times 2+ 10)=40x$

Price with discount for x visits = $57+ x(12 \times 2+ 8)=57+32x$

Now to find For what number of visits will the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

57+32x< 40x

57<8x

7.1<x

So, 8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

8 0

3 years ago