Question

Micah is at a donut shop and wants to choose his own dozen. There are ample glazed,

Answer 1

Answer:

Well lets label them

There are 4 choices

And the 4 choices can make up a dozen

He wants at least 2 jelly donuts

So instead of drawing over a 100 different combinations of donuts and checking them we can Do it like this

Well we know there has to be at least 2 jelly donuts out of the dozen so at least 2 of the donuts are jelly. Now you have 10 donut spaces left

So 1/4*1/4*1/4*1/4 since 4 options is 1/288 Now you have 1/288.

So 288 spaces? I’m not sure haven’t done this in a while just search up probability calcualtions