By what percent will a fraction decrease if its numerator is decreased by 85% and its denominator is decreased by 25%??
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Answer:
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Step-by-step explanation:
In this question we have to test an hypothesis.
The null and alternative hypothesis are:
The significance level is assumed to be 0.01.
The sample of size n=80 gives a proportion of p=61/80=0.7625.
The standard deviation is:
The statistic z is then
The P-value is
The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n() = 100
n() = 9
n() = 20
n() = 35
n() = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n() - n(
) + n(
)
= 72 - 35 - 29 + 9
= <em>17</em>