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Dimas [21]
4 years ago
9

By what percent will a fraction decrease if its numerator is decreased by 85% and its denominator is decreased by 25%??

Mathematics
1 answer:
belka [17]4 years ago
4 0

Answer:

106.67%

Step-by-step explanation:

85% as a fraction is 4/5

25% as a fraction is 3/4

<h2>\frac{4}{5}/\frac{3}{4}=\frac{16}{15} </h2>

Convert 16/15 to a decimal: 1.067

Multiply: 1.067 · 100= 106.67%

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cestrela7 [59]
I got the answer C. This was by multiplying .07 (the decrease) by 5,580,000. Which I then got the number 390,600, which I added to 5,580,000.
6 0
3 years ago
Kyle's car average 380 miles on a 16-gallon tank of gas. How far can he drive on 6 gallons of gas?
mr Goodwill [35]
380 / 16 = x / 6
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4 years ago
Last year mark was 46 inches tall.This year ,Mark's height is 3 inches less than peter's height.Peater is 52 inches tall .How ta
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3 years ago
Read 2 more answers
A salmon is swimming in a river that is flowing downstream at a speed of 2 miles per hour. The slamon can swim 12 miles upstream
Olegator [25]

Answer:

The speed of the salmon in still water is 6 mi/h

Step-by-step explanation:

When an object moves with a speed So (So measured in still water) in a river with speed Sr:

If the object moves along the current (downstream), then the actual speed of the object will be:

S = So + Sr

If the object moves upstream, then the velocity will be:

S = So - Sr

In this case we know the speed of the river downstream is 2 mi/h

Sr = 2mi/h

And we know that the salmon can swim 12 miles upstream in the same time (T) that it can swim 24 miles downstream.

Here you need to remember the relation:

Distance = Time*Speed.

Then we know that:

24 mi = (So + 2mi/h)*T

12 mi = (So - 2mi/h)*T

Now we can take the quotient of these two equations to get:

(24mi/12mi) = ( (So + 2mi/h)*T)/((So - 2mi/h)*T)

2 = (So + 2mi/h)/(So - 2mi/h)

Let's multiply both sides by the denominator of the right part:

2*(So - 2mi/h) = (So + 2mi/h)

2*So - 4mi/h = So + 2mi/h

Now we need to isolate So, the speed of the salmon in still water:

2*So - So = 2mi/h + 4mi/h

So = 6mi/h

The speed of the salmon in still water is 6 mi/h

7 0
3 years ago
Which expression is equivalent to ?<br> x ^-5/3
Dmitry_Shevchenko [17]

Answer:

{x}^{ -  \frac{5}{3} }  \\  \frac{1}{ {x}^{ \frac{5}{3} } }

7 0
3 years ago
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