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Dimas [21]
4 years ago
9

By what percent will a fraction decrease if its numerator is decreased by 85% and its denominator is decreased by 25%??

Mathematics
1 answer:
belka [17]4 years ago
4 0

Answer:

106.67%

Step-by-step explanation:

85% as a fraction is 4/5

25% as a fraction is 3/4

<h2>\frac{4}{5}/\frac{3}{4}=\frac{16}{15} </h2>

Convert 16/15 to a decimal: 1.067

Multiply: 1.067 · 100= 106.67%

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Clark used the order of operations to find the unknown number in 15-12÷3=n what is the value of the unknown number?
lukranit [14]
The order of operations is:

Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction

So division comes first:

\sf 15-12\div 3=n

\sf 15-4=n

Now subtraction:

\boxed{\sf n=11}
5 0
4 years ago
Read 2 more answers
Plz help me find zero x on the triangle and show work thanks​
netineya [11]

Answer:

x= 30 degrees

Step-by-step explanation:

This is an isosceles triangle as indicates by the lines on the sides.

Since the sides lengths are equal, the base angles are  equal

x= 30 degrees

6 0
4 years ago
7/12 - □ = 1/6<br><br><br>□ = ________​
xz_007 [3.2K]
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
4 0
3 years ago
According to the National Institute of Health, about 37% of high school seniors have vaped in the past year. Suppose that a surv
Elodia [21]

Using the Central Limit Theorem, it is found that the mean of the sampling distribution of sample proportions is 0.37.

The <em>Central Limit Theorem</em> establishes that, for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportions has:

  • Mean \mu = p.
  • Standard error s = \sqrt{\frac{p(1 - p)}{n}}

For this problem, about 37% of high school seniors have vaped in the past year, hence p = 0.37.

  • Then, the mean of the sampling distribution of sample proportions is 0.37.

For more on the Central Limit Theorem, you can check brainly.com/question/4086221

8 0
3 years ago
Prove the formula sin 3 A + sin A = 4 sin A cos2A
pantera1 [17]

We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.

In the given question,

We have to prove the formula sin 3A+sin A = 4sinAcos^2A

The given expression is sin 3A+sin A = 4sinAcos^2A

To prove the formula we take the left side terms to the right side terms

The left side is sin 3A+sin A.

As we know that sin 3A = 3sinA − 4sin^3A

To solve the left side we put the value of sin 3A in sin 3A+sin A.

=sin 3A+sin A

=3sinA − 4sin^3A+sin A

Simplifying

= (3sinA+sin A) − 4sin^3A

= 4sinA − 4sin^3A

Taking 4sinA common from both terms

= 4sinA(1 − sin^2A)

As we know that cos^2A=1 − sin^2A. So

= 4sinAcos^2A

We proved the right hand side.

To learn more about formula of trigonometry terms link is here

brainly.com/question/15270423

#SPJ1

5 0
2 years ago
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