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3 years ago

What is the square root 3175 by division method

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

4 0

56.347..........

just simply put the value 3175 under division root and make pairs of 31 and 75.Now think of a number whose square will be nearest to 31 and that ll be 5.Now write 5 in the quotient and 5 also 5 under the divider.Now by multiplying 5 with the 5 in the quotient you ll get 25 write this under 31.And by adding 5 in the divider 5 youll get 10.write this under the divider.no by subtracting 25 from 31 you ll get 6 and by bringing 75 down it ll be 675.Now think of a number again and write it with 10.Like 6 into 6 is 36 and when you multiply 6 with 106 you ll get nearest number to 675 that ll be 636.Now because its giving a remainder just add a .0 in the question and continue to solve it the same way.And as it ll be a continuous answer so just add continuty dots........ or just round it off to nearest whole number

svetoff [14.1K]3 years ago

4 0

Answer:

56.347138347923

Step-by-step explanation:

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g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

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And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

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Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

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Answer:

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Step-by-step explanation:

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