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3 years ago

Please help! i literally suck at geometry

Mathematics

1 answer:

sdas [7]3 years ago

8 0

Don’t say like that!Think you can and you will achieve! :) :)

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Read carefully and choose the name of the student who made the correct statement ..... HELPPP

Taya2010 [7]

Answer:

Nolan is correct.

Step-by-step explanation:

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If you still need help understanding, I'll explain myself.

7 0

3 years ago

Solve the equation. 5x + 10 = 15 A. 3 B. 1 C. 5 D. 25

nikklg [1K]

Answer:

B. 1

Step-by-step explanation:

5x + 10 = 15

-10 -10

5x = 5

÷ 5 ÷ 5

x = 1

5 0

3 years ago

Help!! Please I’m stuck give [10pts]

pishuonlain [190]

Answer:

x = 18

Step-by-step explanation:

To solve this problem, we can use the exterior angle theorem, which means the measure of an exterior angle is the sum of its remote interior angles. In this case, this would mean:

x + 72 = 5x

Since this gives us an equation, we can just solve for x:

x + 72 = 5x

72 = 4x

x = 18

7 0

2 years ago

Select the GCF of these numbers.

Marysya12 [62]

The Greatest Common Factor (GCF) of 25, 5, 11 and 23, 52, 7 is 1, same with 22,3 and 23, 5 and 13, 193, 232.

4 0

3 years ago

Read 2 more answers

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

3 years ago