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aleksandrvk [35]
3 years ago
6

To order the right amount of flooring, you need to know the floor area of the living room shown

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
The answer is 180 i hope i helped you :)
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The length of a rectangle is 2 feet more than 5 its width. The perimeter is 52 feet. Find the dimension of the rectangle
Ber [7]

Answer: The length is 22 feet. The width is 4 feet.

Step-by-step explanation: Create an equation for the length: 2+5w=52.

Now combine the two sides to get 4+10w=52. Plug in some numbers that seem reasonable. I started with 4, checked my work and found that it was right. This problem is all about trial and error.

So, 4+10(4)= 44. Make sure to remember the width, so add 4 for each side: 44+8. 44+8=52. Hope this helps :)


4 0
3 years ago
Read 2 more answers
3 friends are selling items at a bake sale. May makes $23.25 selling bread. Inez sells gift baskets and make 100 times as much a
Zigmanuir [339]

Answer:

May: $23.25

Inez: $2325

Jo: $232.5

Step-by-step explanation:

Inez makes 100 times as much as May. Since May makes $23.25, move the decimal point two places to the right to multiply the number by 100. You will get $2325. Jo makes 1/10 of the money Inez makes. Pretend there is a decimal point at the end of 2325. Move the decimal point one place to the left to divide by 10. You will get $232.5.

8 0
3 years ago
Read 2 more answers
PLEASE SOLVE PLEASE!!​
Oksanka [162]

Answer:

which one do you need?

Step-by-step explanation:

4 0
3 years ago
If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
Please help!! i’ll mark brainliest!!!!
shtirl [24]

Answer:

x^2+11x+30

Step-by-step explanation:

3 0
3 years ago
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