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Fudgin [204]
3 years ago
7

Please help I don't know how to find area so please help

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0
I think that you should imagine what regular shape the figure would have been.
The fact that two sides are 9inches makes me think it would have been a square.
The area of a square is A= l² where l is the length of one side and A=area
A=9*9
A=81 in.²
Next, find the area of the part that is taken away,(it looks like a triangle). to find that, if the figure was a square, the length on top would be 9 not 5, so the length gone is 9-5=4, so the base of the triangle is 4,
If the figure was a square, the length on the other side would be 9 not 4 so the length gone is 9-4=5, so the height of the triangle is 5
the area of a triangle is A= 1/2bh, where A is area, b is base and h is height.
A=1/2*4*5   A=10 so the area of the part gone is 10 inches²
The area of the figure is the area of the square -the area of the triangle
A=81-10
A=71inches²

,

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Read 2 more answers
SOMEONE PLZZZ HELP ME THIS IS DUE IN LIKE 5 MINS (I WILL MARK BRAINLIEST)
andrew-mc [135]

Answer:

1) x = 8

2) ∠RPS = 36°

Step-by-step explanation:

<u>GIVEN :-</u>

  • ∠QPS = 180°
  • ∠QPR = 7x + 88
  • ∠RPS = 3x + 12

<u>TO FIND :-</u>

  1. Value of x
  2. Measure of ∠RPS

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

In a straight line , if there are two angles such that their sum is equal to straight angle (or 180° in other words) , then those angles are known as linear pair.

<u>PROCEDURE :-</u>

1)

Measure of ∠QPS = 180° and it comprises of ∠QPR & ∠RPS.

⇒ ∠QPR & ∠RPS are linear pair.

⇒ ∠QPR + ∠RPS = 180°

⇒ 7x + 88 + 3x + 12 = 180°

⇒ 10x + 100 = 180

⇒ 10x = 180 - 100 = 80

⇒ x = 80/10 = 8

2)

x = 8. So,

∠RPS = 3×8 + 12 = 24 + 12 = 36°

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