Please help I don't know how to find area so please help
1 answer:
I think that you should imagine what regular shape the figure would have been.
The fact that two sides are 9inches makes me think it would have been a square.
The area of a square is A= l² where l is the length of one side and A=area
A=9*9
A=81 in.²
Next, find the area of the part that is taken away,(it looks like a triangle). to find that, if the figure was a square, the length on top would be 9 not 5, so the length gone is 9-5=4, so the base of the triangle is 4,
If the figure was a square, the length on the other side would be 9 not 4 so the length gone is 9-4=5, so the height of the triangle is 5
the area of a triangle is A= 1/2bh, where A is area, b is base and h is height.
A=1/2*4*5 A=10 so the area of the part gone is 10 inches²
The area of the figure is the area of the square -the area of the triangle
A=81-10
A=71inches²
,
The fact that two sides are 9inches makes me think it would have been a square.
The area of a square is A= l² where l is the length of one side and A=area
A=9*9
A=81 in.²
Next, find the area of the part that is taken away,(it looks like a triangle). to find that, if the figure was a square, the length on top would be 9 not 5, so the length gone is 9-5=4, so the base of the triangle is 4,
If the figure was a square, the length on the other side would be 9 not 4 so the length gone is 9-4=5, so the height of the triangle is 5
the area of a triangle is A= 1/2bh, where A is area, b is base and h is height.
A=1/2*4*5 A=10 so the area of the part gone is 10 inches²
The area of the figure is the area of the square -the area of the triangle
A=81-10
A=71inches²
,
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Answer:
each of the 12 turns is 150°
Step-by-step explanation:
If we number the points of the star 1–12, in order for the star to be symmetrical, each point must connect to two points symmetrically located around the centerline.
That is, point 1 may connect to points {2, 12} or {3, 11} or {4, 10}, or {5, 9} or {6, 8} or {7, 7}. For each of these connections, the angle made at the point of the "star" is, respectively, 150°, 120°, 90°, 60°, 30° or 0°. For these angles, the figure obtained will be ...
150° - dodecagon, a 12-sided figure
120° - hexagon
90° - square
60° - equilateral triangle
30° - 12-pointed star
0° - straight line
The two 12-pointed figures are shown in the attachment.
__
We suspect the star you're interested in is the one with points that are 30°. In order to have that point angle, the spider must make a turn of 180° -30° = 150°.
The spider will make 12 turns of 150°, for a total of 1800°, for a total of 5 full turns of 360°.
