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ikadub [295]
3 years ago
8

Help i have to turn this in later

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
C since they are reflected
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Transform the given quadratic function into vertex form f(x) = quadratic function into vertex form f(x) = quadratic function int
melisa1 [442]

Answer:

Vertex form: f(x) =(x +\frac{7}{2})^2 -\frac{53}{4}

The vertex is (-\frac{7}{2},-\frac{53}{4})

Step-by-step explanation:

For a general quadratic function the form is:

ax ^ 2 + bx + c

For the function

f(x) = x ^ 2+ 7x -1

The values of the coefficients for the function are the following: a = 1, b =7, c = -1

Take the value of b and divide it by 2. Then, the result obtained squares it.

\frac{b}{2}= \frac{7}{2}

(\frac{b}{2})^2=(\frac{7}{2})^2=\frac{49}{4}

Add and subtract \frac{49}{4}

f(x) = (x ^ 2 +7x +\frac{49}{4}) -\frac{49}{4}- 1

Write the expression of the form

f(x) = (x+\frac{b}{2})^2 +k

f(x) =(x +\frac{7}{2})^2 -\frac{53}{4}

The vertex is (-\frac{7}{2},-\frac{53}{4})

6 0
3 years ago
Explain in a full sentence how 4<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B6%7D" id="TexFormula1" title="\frac{2}{6}" al
Luda [366]

Answer:

Step-by-step explanation:

6 0
4 years ago
If a company buys an item at a wholesale price of $45, which of the following would make sense as a retail price to charge the c
boyakko [2]

Answer:

Step-by-step explanation:

buys it for $ 45

well...you know the business is gonna want to make a profit...so they would have to sell it for more then they bought it for.

I would say $ 60 or $ 80

4 0
3 years ago
X+y+z=-6<br> x-y+3z=-18<br> 2x+2y+2z=-8
Temka [501]

Answer:

Step-by-step explanation:

hello :

the system is : x+y+z=-6.....(1)

                      x-y+3z=-18.....(2)

                   2x+2y+2z=-8.....(3)

use (3): 2(x+y+z) = - 8    so : x+y+z = -4

use (1) : x+y +z = -6          -6=-4 false

no solutions

3 0
2 years ago
Read 2 more answers
Simplify (tan^2 x/sec x + 1) + 1
Iteru [2.4K]
X would equal -2 so another words  please mark meas a brainlyiest answer

4 0
3 years ago
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