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LUCKY_DIMON [66]
3 years ago
9

A model train is 9 centimeters long. The actual engine is 18 meters long. What is the scale of the model? Tracy has a model trai

n set that is 59 centimeters long. How long would the train be in real life?
Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

1 cm : 2m

1 cm = 2m

118m

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

18 / 9 = 2 : 1

59 x 2 = 118

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Goshia [24]
1) 100 * 40 = 4000 (cm²) the area of rectangle
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3) 4000 + 600 = 4600 (cm²)

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3 years ago
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zloy xaker [14]
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8 0
4 years ago
Sam is a waiter at a local restaurant where he earns wages of $6 per hour. Sam figures that he also earns about $2.50 in tips fo
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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
Verizon [17]
A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}
\\
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Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
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Divide both sides by 0.35:
1.9805/0.35 = √n

Square both sides:
(1.9805/0.35)² = n
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8 0
3 years ago
What value of x make this proportion tire 120/165= x/11
mrs_skeptik [129]
165÷11=15
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7 0
4 years ago
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