Thus is a linear equation, so you want to isolate m so you can compare the variable m to a constant.
You begin by getting rid of -9 by adding 9 (its opposite) since a negative plus a positive can me zero. Then you add 9 to (-13) which is the same as 13-9 but with a negative value, so you get -4.
The answer is -4
G/3 - 7 = 15 --> g/3-7+7 = 15+7 --> g/3 = 22 --> g/3*3 = 22*3 --> g = 66
Answer:
Step-by-step explanation:
1-x²=-(x²-1)=-(x-1)(x+1)
L.C.M.=(x+1)(x-1)³