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drek231 [11]
3 years ago
10

I am lost so i need the correct answer and how to start the problem

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

-9 + (-2)

Step-by-step explanation:

Ignore where there first line starts just look at where it points to. -9, then it points to a digit to units down, so -11. it could also be -9 -2

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NemiM [27]
The answer to your question would be 150 (c)
6 0
4 years ago
What numbers are a distance of 1/2 unit from 3/5 on a number line? Select the locations on the number line to plot the points.
Allushta [10]
<span>The numbers that are a distance of 1/2 unit from 3/5 on a number line are the numbers that are 1/2 units to the right and to the left of 3/5 on the number line.

The numbers are given by 3/5 - 1/2 and 3/5 + 1/2.

The numbers are 1/10 and 1 1/10
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3 0
4 years ago
Read 2 more answers
Whats is the area of this kite? <br><br> Help please..!
blagie [28]
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3 0
3 years ago
Norton can mow the large lawn in about 5 hours. When he works with
astra-53 [7]

Answer:

7.5 hours

Step-by-step explanation:

The key here is to find out how much can be done in the same amount ot time

the least common multiple of 5 hrs and 3 hrs is 15hrs

In 15 hours:

- At 5 hours per lawn Norton could mow 15/5 = 3 lawns

- At 3 hours per lawn together thay could mow 15/3 = 5 lawns

In 15 hours Jesse would mow 5 - 3 = 2 lawns

15 hours/ 2 lawns = 7.5 hours per lawn

7.5 hours

--------------------

Here's the math

1 lawn/5hrs + x = 1 lawn / 3hrs

1/5 + x = 1/3

Subtract 1/5 from both sides

x = 1/3 - 1/5

x = 5/15 - 3/15

x = 2/15

x = 2lawns/15 hrs

15hrs/2lawns = 7.5 hrs per lawn

7.5 hours

5 0
3 years ago
Find the area of a square whose diagonal length is 32 CM​
BigorU [14]

Answer:

512cm^2

Step-by-step explanation:

Let's imagine cutting the square down that diagonal. Now, we have two isosceles right triangles with a hypotenuse with length 32cm. Let's take one of those triangles for now and focus on it. Let's give the one of the legs of a triangle some length x. Since both legs are the same length, by the Pythagorean theorem:

x^2+x^2=32^2\\\\2x^2=1024\\\\x^2=512\\\\x=\sqrt{512}

Since this leg makes up one side of the square, we can use it to calculate the area of the square, which is just the side length squared:

A=(\sqrt{512})^2 = 512

7 0
3 years ago
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