The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.
<h3>What is the Nernst Equation?</h3>
The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:
![\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}](https://tex.z-dn.net/?f=%5Cmathbf%7BE_%7Bcell%7D%20%3D%20E_o%20-%20%5Cdfrac%7B0.059%7D%7Bn%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%2B%5D%7D%7B%5BMn%5E%7B2%2B%7D%5D%7D%7D)
where;
- n = Number of electrons = 2
= Initial voltage = 0.77 V
= Cell voltage = 0.78 V![\mathbf{[Mn^{2+}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5BMn%5E%7B2%2B%7D%5D%7D)
= Manganese concentration = 0.050 M
Replacing the values into the above equation, we have:
![\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20%3D%200.77%20-%20%5Cdfrac%7B0.059%7D%7B2%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20-0.77%3D%20-0.0296%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7Blog%5E%7B-1%7D%20%28-0.3378%29%20%3D%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
Learn more about using the Nernst equation here:
brainly.com/question/24258023
Note that with |x|, the value x will always be positive when simplified. This means that:
B) |-3.5|, |4.2|, |-9| is your answer, because it becomes, 3.5, 4.2, 9
hope this helps
E. Redundant. In my opinion most of the opinions are contradictory because invalid, falsified, and redundant have closely similar meanings
The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
Read more about Smallest Integer at; brainly.com/question/13329614
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