Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
Answer:395.75lb
Step-by-step explanation:see attachment
Answer:
10
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
2x³y³ + 3xy - 3x³y³ + x²y - xy + 2x²y
x = -1
y = 2
<u>Step 2: Evaluate</u>
- Substitute: 2(-1)³(2)³ + 3(-1)(2) - 3(-1)³(2)³ + (-1)²(2) - (-1)(2) + 2(-1)²(2)
- Exponents: 2(-1)(8) + 3(-1)(2) - 3(-1)(8) + 1(2) - (-1)(2) + 2(1)(2)
- Multiply: -16 - 6 + 24 + 2 - (-2) + 4
- Simplify: -16 - 6 + 24 + 2 + 2 + 4
- Subtract: -22 + 24 + 2 + 2 + 4
- Add: 2 + 2 + 2 + 4
- Add: 4 + 2 + 4
- Add: 6 + 4
- Add: 10
Answer:
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Answer: i think its 4 if my calculations are right
Step-by-step explanation:
