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zloy xaker [14]
3 years ago
5

Math help @Alessandroarenas

Mathematics
1 answer:
frez [133]3 years ago
7 0

Accordinly to the details, i think that A could work.

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if a quadratic equation with real coefficients has a discriminant of -36 then what type of roots does it have
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Step-by-step explanation:

We have,

If a quadratic equation with real coefficients has a discriminant of -36.

The general form of quadratic equation is :

ax^2+bx+c=0

The discriminant of this equation is : D=b^2-4ac

If D=0, it will have 1 real roots

If D>0, it will have 2 real roots

If D<0, it will have no real roots

We have,

D = -36 < 0, so, the quadratic equation will have no real roots.

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