7 2/15+52/3+9 13/15 a. 20 2/3 B.21 10/15 C.21 2/3 D.22 2/3 pls do i will mark brainlessness

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for

swat32

Let the price of flowers in September be x, then (100 + 20)/100 * x = $1.50
120/100 * x = $1.50
1.2x = $1.50
x = $1.50/1.2 = $1.25
The price of flowers in September is $1.25

Total money realised in September = $1.25 x 900 = $1,125
40% earned = 0.4 x $1,125 = $450

Total money realised in October = $1.50 x 700 = $1,050
40% earned = 0.4 x $1,050 = $420

The class earned more money in September and they earned $30 more than in October.

7 0

2 years ago

1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th

Kryger [21]

Answer:

a

$P = 0$ OR $P = 135$

b

$P > 0$ and $P < 135$

OR

$P > 0$ and $P < 135$

c

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

d

$P = 67.5$

Step-by-step explanation:

From the question we are told that

The population model is $\frac{dP}{dt} = 0.2P(1 - \frac{P}{135} )$

Generally at equilibrium

$\frac{dP}{dt} = 0$

So

$0.2P = 0$

=> $P = 0$

Or

$(1 - \frac{P}{135} ) = 0$

=> $P = 135$

Thus at equilibrium P = 0 or P = 135

Generally when the population is increasing we have that

$\frac{dP}{dt} > 0$

So

$0.2P > 0$

=> $P > 0$

and

$(1 - \frac{P}{135} ) > 0$

$P < 135$

Now when the first value of P i.e $P< 0$ for $\frac{dP}{dt} > 0$

$P_2 > 135$

So when population increasing the values of P are

$P > 0$ and $P < 135$

OR

$P > 0$ and $P < 135$

So to obtain initial values of P where the population converge to the carrying capacity as $t \to [\infty]$

The rate equation can be represented as

$\frac{dP}{dt} = \frac{1}{5}P (1 - \frac{P}{135} )$

So we will differentiate the equation again we have that

$\frac{d^2 P}{dt^2} = \frac{(1 - \frac{P}{135} )}{5} - \frac{P}{675}$

Now as $t \to [\infty]$

$\frac{d^2 P}{dt^2} \to 0$

So

$\frac{(1 - \frac{P}{135} )}{5} - \frac{P}{675} = 0$

=> $\frac{(1 - \frac{P}{135} )}{5} = \frac{P}{675}$

=> $P = 67.5$

5 0

3 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

zhenek [66]

Answer:

The intensity on a screen 70 ft from the light is 1.728 foot candle.

Step-by-step explanation:

Given that,

The magnitude of intensity $I$ of light varies inversely as the square of the magnitude of distance D from the source.

That is

$I\propto \frac{1}{D^2}$

Then,

$\frac{I_1}{I_2}=\frac{D_2^2}{D_1^2}$

Given that,

The magnitude of intensity of illumination on a screen 56 ft from a light is 2.7 foot-candle.

Here,

$I_1$ =2.7 foot-candle, $D_1$ = 56 ft

$I_2$ =?, $D_2$ = 70 ft.

$\frac{I_1}{I_2}=\frac{D_2^2}{D_1^2}$

$\Rightarrow \frac{2.7}{I_2}=\frac{70^2}{56^2}$

$\Rightarrow \frac{I_2}{2.7}=\frac{56^2}{70^2}$

$\Rightarrow {I_2}=\frac{56^2\times 2.7}{70^2}$

$\Rightarrow {I_2}=1.728$ foot-candle

The intensity on a screen 70 ft from the light is 1.728 foot candle.

3 0

3 years ago

A cereal box in the shape of a rectangular prism has a volume of 18x^3 - 3x^2 - 6x. What are three possible linear expressions f

Tatiana [17]

From factoring, the volume of a rectangular prism can be written as:

3x * (2x+1) * (3x-2).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

The question gives: 18x³-3x²-6x. You can see that, initially, 3x is a common term. Therefore, you can write: 3x * (6x²-x-6) . Nonetheless, the question also asks 3 linear expressions, here only you have one (3x).

Thus, you should factor the expression (6x²-x-6) into two linear expressions: (2x+1)* ( 3x-2).

Thus, the volume of a rectangular prism can be written as:

3x * (2x+1) * (3x-2)

Learn more about the factoring here:

brainly.com/question/11579257

#SPJ1

3 0

1 year ago

3,6,19 acute, obtuse, or not a triangle

Helen [10]

I believe it’s an obtuse triangle

8 0

2 years ago

Read 2 more answers