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4 years ago

In ΔKLM, the measure of ∠M=90°, the measure of ∠K=76°, and KL = 27 feet. Find the length of MK to the nearest tenth of a foot.

Mathematics

1 answer:

coldgirl [10]4 years ago

6 0

Answer:

6.5 ft ft

Step-by-step explanation:

Angle L will be 180-90-76=14

Using the sine rule $\frac {A}{sina}=\frac {B}{sinb}=\frac {C}{sinc}$

Relating to the above set up

$\frac {ML}{sin76}=\frac {27}{sin90}=\frac {KM}{sin14}$

Taking only the first two parts then

$\frac {MK}{sin14}=\frac {27}{sin90}\\MK=\frac {27sin14}{sin90}=6.53189118119109ft\approx 6.5 ft$

Therefore, rounded off to the nearest tenth, distance will be 6.5 ft

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To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
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$e$ is the Euler's constant
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$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
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Now that we have $r$ , we can write a function to model this scenario:
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$A(10)=1250e^{(-0.2231)(10)$
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3 years ago

Two cyclists start at the same time from opposite ends of a course that is 45 miles long. One cyclist is riding at 14 mph and th

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If the distance is 45 miles and speed of both cyclist is 14 and 16 miles per hour then they will take time of 1.5 hour to meet.

Given First cyclist is riding at 14 miles per hour and second at 16 miles per hour. The distance is 45 miles.

We know that speed is the distance covered by an object in a particular period of time.

Speed=distance/time.

It is expressed as kilometers per hour or miles per hour, etc.

If both riders are riding towards each other then the speed will be 16+14 =30 miles per hour.

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Time =distance/speed

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Hence if first cyclist is riding at 14 miles per hour and second is riding at 14 miles per hour and the distance is 45 miles then they will meet after 1.5 hours.

Learn more about speed at brainly.com/question/4931057

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