Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
Y=-2(x-4)^2-6
The -6 makes it shift from origin(0,0) to (0,-6)
Then the -4 inside with x, makes it shift to the right by for, so the center would be now instead of (0,0), (4,-6).
As it has a negative A factor, it is a parabola open downwards, so the center is the maximum value.
Answer: (4,-6)
Hope you get it!
awnser:
y
=
62
/3
Step-by-step explanation:
5(6)+3y=92
