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3 years ago

50 POINTS! Show All Work!

Mathematics

2 answers:

olasank [31]3 years ago

7 0

Let the number of chickens = c.

Let the number of pigs = p.

A chicken has 1 head and 2 legs.

c number of chickens have c heads and 2c legs.

A pig has 1 head and 4 legs.

p number of pigs have p heads and 4p legs.

There are 40 heads.

Equation for heads:

c + p = 40

There are 110 legs.

Equation for legs:

2c + 4p = 110

System of equations:

c + p = 40

2c + 4p = 110

Solve the first equation of the system of equations for c:

c = 40 - p

Substitute 40 - p for c in the second equation:

2c + 4p = 110

2(40 - p) + 4p = 110

80 - 2p + 4p = 110

80 + 2p = 110

2p = 30

p = 15

Now substitute p = 15 in the first equation to find c.

c + p = 40

c + 15 = 40

c = 25

There are 25 chickens and 15 pigs.

vichka [17]3 years ago

4 0

Answer:

There are 25 chickens and 15 pigs. I did my research/work outside of brainly. Don't worry, the person above me also got the same answer so we're all good. Either way, I hope this helps you! :)

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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

$\\$

To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

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