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zalisa [80]
3 years ago
12

50 POINTS! Show All Work!

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Let the number of chickens = c.

Let the number of pigs = p.

A chicken has 1 head and 2 legs.

c number of chickens have c heads and 2c legs.

A pig has 1 head and 4 legs.

p number of pigs have p heads and 4p legs.

There are 40 heads.

Equation for heads:

c + p = 40

There are 110 legs.

Equation for legs:

2c + 4p = 110

System of equations:

c + p = 40

2c + 4p = 110

Solve the first equation of the system of equations for c:

c = 40 - p

Substitute 40 - p for c in the second equation:

2c + 4p = 110

2(40 - p) + 4p = 110

80 - 2p + 4p = 110

80 + 2p = 110

2p = 30

p = 15

Now substitute p = 15 in the first equation to find c.

c + p = 40

c + 15 = 40

c = 25

There are 25 chickens and 15 pigs.

vichka [17]3 years ago
4 0

Answer:

There are 25 chickens and 15 pigs. I did my research/work outside of brainly. Don't worry, the person above me also got the same answer so we're all good. Either way, I hope this helps you! :)

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B If the average battery life really is 5 hours, then a sample of 10 observations having a sample mean of 4.25 hours or lower would only occur about 3.8% of the line.

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It depends on the test statistic z, as follows:

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  • For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is 2 multiplied by 1 subtracted by the p-value of z, which means that the p-value for a two-tailed test is twice the p-value of a one-tailed test.

In this problem, a left-tailed test is used, as we are testing if the mean is less than 5 hours.

The sample mean from the 10 times was of 4.25, and the p-value is of 0.038, which means that the area to the left of Z under the normal curve is of 0.038, that is, a sample mean of 4.25 hours or lower would only occur about 3.8% of the line, hence option B is correct.

You can learn more about p-values at brainly.com/question/13873630

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