Answer:
the present age of the father be x and the present age of the son be y.
It is given that man is 24 years older than his son that is:
x=y+24
x−y=24..........(1)
Also, 12 years ago, he was five times as old as his son that is:
(x−12)=5(y−12)
x−12=5y−60
x−5y=−60+12
x−5y=−48..........(2)
Now subtract equation 1 from equation 2 to eliminate x, because the coefficients of x are same. So, we get
(x−x)+(−5y+y)=−24−48
i.e. −4y=−72
i.e. y=18
Substituting this value of y in (1), we get
x−18=24
i.e. x=24+18=42
Hence, the present age of the father is 42 years and the present age of the son is 18 years.
Step-by-step explanation:
