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Olegator [25]
2 years ago
9

If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
7 0

Answer:

[DATA EXPUNGED]

Step-by-step explanation:

[REDACTED]

solong [7]2 years ago
7 0

Answer:

Step-by-step explanation:their are many vbarity

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Please help me! i dont know what to do... And my weekend depends on you
vladimir2022 [97]

Answer:

the signed number 7

Step-by-step explanation:

it was 15 minutes and she  used 7.12899 gallongs

7 0
3 years ago
Divide £50 into the ratio 1:4
Helga [31]
Don't know how to type the symbole infront of the 50 so I will subsitute
£50=$50

so 1:4
add it up
1+4=5

so 5 total units
$50=5 units
divide by 5
$10=1 unit

so 1:4=10:10 times 4=10:40

the answer is 10:40

8 0
3 years ago
Read 2 more answers
If the diagonal of a square is approximately 12.73, what is the length of its sides?
Alja [10]

Answer:

The length of the sides of the square is 9.0015

Step-by-step explanation:

Given

The diagonal of a square = 12.73

Required

The length of its side

Let the length and the diagonal of the square be represented by L and D, respectively.

So that

D = 12.73

The relationship between the diagonal and the length of a square is given by the Pythagoras theorem as follows:

D^{2} = L^{2} + L^{2}

Solving further, we have

D^{2} = 2L^{2}

Divide both sides by 2

\frac{D^{2}}{2} = \frac{2L^{2}}{2}

\frac{D^{2}}{2} = L^2

Take Square root of both sides

\sqrt{\frac{D^{2}}{2}} = \sqrt{L^2}

\sqrt{\frac{D^{2}}{2}} = L

Reorder

L = \sqrt{\frac{D^{2}}{2}}

Now, the value of L can be calculated by substituting 12.73 for D

L = \sqrt{\frac{12.73^{2}}{2}}

L = \sqrt{\frac{162.0529}{2}}

L = \sqrt{{81.02645}

L = 9.001469325

L = 9.0015 (Approximated)

Hence, the length of the sides of the square is approximately 9.0015

7 0
3 years ago
In your own words, explain the steps you would need to take to find slope from data in a table. Brainly work your magic.
mr_godi [17]

Answer:

In order to find the slope, you need to find the difference in the x values and the difference in the y values. To do this, you write out y2-y1/x2-x1, insert your x and y values, and get your answer. Then, you find your y-intercept (where the x value is 0).

6 0
3 years ago
The value of x-y is negative, and x and y are both positive. What can you conclude about the values of x
Stolb23 [73]
Well for two positive numbers subtracted to equal a negative number, the first number must have a value that is less than the second number. (Ex. 3-4= -1) In this case, you can conclude that x is less than y! (x<y)
3 0
3 years ago
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