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Naily [24]
2 years ago
10

a line passes through the point (-9,1) and has a slope of 4/3. Write an equation in slope-intercept form for this line.

Mathematics
2 answers:
Strike441 [17]2 years ago
6 0

Answer:  y=4/3x+1

Step-by-step explanation:

The formula is Y=mx+b

b is the y-intercept and MX is slope

belka [17]2 years ago
5 0
Y=4/3x+1. This will be your answer.
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Whitch of the following is closest to 8 62 61 65 66
Natasha2012 [34]

Answer:

If the question is which is closest to 8, the answer is 61

Step-by-step explanation:

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Write a slope intercept equation for a line passing through the point (4,-2) that is parallel to the line 4x+5y=7. Then write a
LuckyWell [14K]

First, the equation needs to be put into slope-intercept form, which is y = -4/5x + 7/5. Then, you need to know what parallel and perpendicular lines are. REMEBER, parallel lines have the same slope, and perpendicular lines have slopes whose product equal -1. You just need to substitute. For the parallel line, -2 = -4/5(4) + b, and b = 6/5, so y = -4/5x + 6/5. For the perpendicular line, the slope is 5/4. Now substitute. -2 = 5/4(4) + b, and b = -7, so y = 5/4x -7.

3 0
3 years ago
Square is 19 yd.² what is the length of each side
olga_2 [115]
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6 0
3 years ago
Please help me! II'll give you brainliest!
sweet [91]

Answer:

x=7

Step-by-step explanation:

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5 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
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