a line passes through the point (-9,1) and has a slope of 4/3. Write an equation in slope-intercept form for this line.
2 answers:
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Answer:
Step-by-step explanation:
check attachment
f(x,y)=xy Δf(2,5)
fx=y = 5
fy=x = 2
Gradient Vector:
<5,2>
Tangent Vector:
0=fx(x-2) + fy(y-5)
0=5(x-3) + 2(y-2)
11=5x+2y
