A: 3.2/294=12/T
<span>T=1102.5 K </span>
<span>*** </span>
<span>*** </span>
<span>b: V/T => V/1088 = 4000/294 </span>
<span>V = 14802.7 L = 14.8 m^3 </span>
<span>*** </span>
<span>*** </span>
<span>c. </span>
<span>pV/T </span>
<span>1.1*V/294 = 12*15000/1088 </span>
<span>V= 48.64 m^3</span>
I think is 4000 because when it's sad 1 singnificant figure you have to round the first name which 4
Answer:
I don’t see a graph
Step-by-step explanation:
Answer:
$14.39
Step-by-step explanation:
The formula for continuous compounding of interest is:
A = Pe^(rt), were P is the initial dollar amount, A is the final amount, r is the interest rate as a decimal fraction, and t is the time in years.
Here we have $2109 = $500e^(10r) and need to solve for r.
To do this, take the natural log of both sides, obtaining:
ln 2109 = ln 500+ 10r.
Then 10r = ln 2109 - ln 500, and
ln 2109 - ln 500
r = --------------------------------------------
10
= .1439
The interest rate was 14.39%.
The solution is x = 2 and y = 4
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
y = 2x -------- eqn 1
x = -y + 6 ----------- eqn 2
We can solve the system of equations by substitution method
<em><u>Substitute eqn 1 in eqn 2</u></em>
x = -2x + 6
Move the variables to one side and constants to other side
x + 2x = 6
3x = 6
Divide both sides of equation by 3
x = 2
<em><u>Substitute x = 2 in eqn 1</u></em>
y = 2(2)
y = 4
Thus the solution is x = 2 and y = 4
