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2 years ago

Evaluate function expression -2×f(-6)-7xg(-7)

Mathematics

2 answers:

marin [14]2 years ago

5 0

Answer:

-12xf+49xg

Step-by-step explanation:

2xf(-6)-7xg(-7)

-2xf*6+7xg*7

Gives you -12xf+49xg

SOVA2 [1]2 years ago

5 0

Answer: wym

Step-by-step explanation:

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-3x-5=16<br> what is x in the equation

bezimeni [28]

Answer:

x=−7

Step-by-step explanation:

Step 1: Add 5 to both sides.

−3x−5+5=16+5

−3x=21

Step 2: Divide both sides by -3.

−3x/−3=21/−3

7 0

3 years ago

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Write the following quadratic in vertex form X^2-10x+7

grin007 [14]

Hello,

y=x²-10x+7=x²-2*5x+25-25+7=(x-5)²-18
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2 years ago

The question is in the screenshot

Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < $\pi$ /2 => tan x > 0

As 0< y < $\pi$ /2 => tan y > 0

We have the formula:

$\frac{1}{sin^{2}x } =1 + cot^{2}x$ => $\frac{1}{(8/17)^{2} }$ = $1+cot^{2}x$ => $cot^{2} x=225/64$

As tan x = 1/(cotx) => $tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}$

As tan x > 0 => tan x = 8/15

$\frac{1}{cos^{2}y } = 1+tan^{2}y$ => $\frac{1}{(3/5)^{2} } = 1 + tan^{2} y$ => $tan^{2}y=\frac{16}{9}$

As tan y > 0 => tan y = 4/3

As tan (x-y)= $\frac{tan x - tan y}{1+ tanx * tany}$ $=\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}$

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3 years ago

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Tcecarenko [31]

The solution would be x=0 because the statement is false.

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xeze [42]

Answer:

Step-by-step explanation:

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3 years ago

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Evaluate function expression -2×f(-6)-7xg(-7)​

Evaluate function expression -2×f(-6)-7xg(-7)