A. the first box is 7
the second box is 2
the third box is 100
the fourth box is 6.5
RULE: times 3 + 2
b. the first box is 45/2
the second box is -0.75
the third box is 0
the fourth box is 2.75
RULE: times 5/2
c. the first box is 1 1/2
the second box is 6
the third box is -4
the fourth box is -1.75
RULE: times half add one
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer:
No real roots
Step-by-step explanation:
Roots of a quadratic are the x-intercepts of the graph
Answer:
-3m+2/3. 2/3 is a fraction
Step-by-step explanation:
I believe the answer is 2x+2y= 20-21 or 2x+2y= -1. Think about Standard Form= Ax+By= C
