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3 years ago

HELP ASAP I WILL GIVE BRAINLYIST

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

Answer:

1,728cm squared

Step-by-step explanation:

1. Break the Composite Figure into smaller shapes such as, rectangles, triangles, and squares.

2. Use the area formula for rectangles, triangles, and squares to find the area of each smaller shape.

3. Add the area of the smaller shapes together to get the area of the entire Composite Figure.

Hope this is correct and helps :[]).

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Simplify -8 + 6(b - 1). -2 b - 1 6 b - 14 6 b - 9 -2 b + 2

Paul [167]

Answer:

-14-158b

Step-by-step explanation:

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3 years ago

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If h(x) = (f o g)(x) and h(x) = sqrt(x+5), find g(x) if f(x) = sqrt(x+2)

agasfer [191]

Answer:

g(x) = x + 3

Step-by-step explanation:

<h3>Given</h3>

h(x) = (f ο g)(x)
h(x) = $\sqrt{x+5}$
f(x) = $\sqrt{x+2}$

g(x)

<h3>Solution</h3>

(f ο g)(x) = f(g(x))

<u>Substitute x with g(x) and solve for g(x):</u>

$\sqrt{x+5}$ = $\sqrt{g(x)+2}$
x + 5 = g(x) + 2
x + 3 = g(x)
g(x) = x + 3

7 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

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3 years ago

You have a credit card with an initial balance of $3,168.00 and an interest rate of 12.75% apr. if you make no payments on the c

zaharov [31]

A=p(1+i/m)^mn
P=3168
i=0.1275
M=12
n=3/12
A=3,168×(1+0.1275÷12)^(12*3/12)
A=3,270.06

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3 years ago

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Simplify: 3x^2-8x+4 and show work please

Bad White [126]

believe what you're asking is to turn the trinomial into two binomials

So you first have to get 3x²; the only way to get this is

(3x )(x ) when multiplying that, you would get 3x²

when dealing with the -8x and the 4, you must find numbers that are factors of four (when multiplied together they will equal 4) and will multiply with the x's to get -8

(3x-2)(x-2)

you can tell that this is the answer because when you multiply though you will get:

3x-2x²-6x+4

or: 3x²-8x_4

Hope this helped

5 0

3 years ago