Answer:
D. (-2, -6) and (5,15)
Step-by-step explanation:
When you set the equations together, you get x^2-3x-10. You then set this equation equal to zero and get (x-5)(x+2) or x=-2 and x=5. Then, plug these x-values into each equation to get your y-values.
Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
Answer:
TWU is congruent to WUV
(I actually don't know if that's how I'm supposed to answer it but do what you will)
Answer:
-79
Step-by-step explanation:
5ac-2b
5(-3)(5) - 2(2)
-75-4
-79
substitute values and then solve
Answer:
0
Step-by-step explanation:
You should prolly turn the line into slope intercept form, y = mx + b
m being the slope
b being the y intercept
The line intercepts the y-axis at -1 so b = -1
From the point of (0,-1) you go up one and left two, that means the slope is -1/2

y = 1 - 1
y = 0
When x = -2, y = 0