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Irina18 [472]
3 years ago
15

What is the density in kilograms per cubic centimeter of 0.0 2.391 and 0.0197 together

Mathematics
1 answer:
Zanzabum3 years ago
3 0
Sjlhljsahljskksalkj asjhldsa s kslka lks akl s
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Factor the expression 54x+8154x+81 using the GCF.<br> 54x+81=54x+81=
nadya68 [22]
We know that GCF stands for Greatest Common Factor and hence we need to apply this in solving the given problem. The solution is shown below:
54x+8154x+81
Combine same terms, we have:
8208X+81
Factoring with the greatest common factor which is 27
304x+3
The answer for the factored expression is 304X + 3.

6 0
3 years ago
Can anyone help me with this question
faust18 [17]

Answer:

Step-by-step explanation:

Like your other question, let's break it down systematically

6x + 9y - 9(6x - 3y + 8z)

Use the distributive property

6x + 9y - <u>9(6x - 3y + 8z)</u>

6x + 9y - 54x - 27y + 72z

Match like terms

6x - 54x = -48x

9y - 27y = -18y

72z - 48x - 18y

6 0
3 years ago
Solve the system using any method.<br> 6x+2y =7<br> y= 2-3x
Drupady [299]

Answer:

there is no solution

3 0
3 years ago
Read 2 more answers
Use the Midpoint Rule with n = 5 to estimate the volume V obtained by rotating about the y-axis the region under the curve y = 1
velikii [3]

Using the shell method, the volume is given exactly by the definite integral,

2\pi\displaystyle\int_0^1x(1+9x^3)\,\mathrm dx

Splitting up the interval [0, 1] into 5 subintervals gives the partition,

[0, 1/5], [1/5, 2/5], [2/5, 3/5], [3/5, 4/5], [4/5, 5]

with left and right endpoints, respectively, for the i-th subinterval

\ell_i=\dfrac{i-1}5

r_i=\dfrac i5

where 1\le i\le5. The midpoint of each subinterval is

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}{10}

Then the Riemann sum approximating the integral above is

2\pi\displaystyle\sum_{i=1}^5m_i(1+9{m_i}^3)\frac{1-0}5

\dfrac{2\pi}5\displaystyle\sum_{i=1}^5\left(\frac{2i-1}{10}+9\left(\frac{2i-1}{10}\right)^4\right)

\dfrac{2\pi}{5\cdot10^4}\displaystyle\sum_{i=1}^5\left(16i^4-32i^3+24i^2+1992i-999\right)=\frac{112,021\pi}{25,000}\approx\boxed{14.08}

(compare to the actual value of the integral of about 14.45)

3 0
3 years ago
Please help me i will give brainliest!
omeli [17]

Answer:

10

Step-by-step explanation:

1x2x2.5=5

5/0.5=10

6 0
3 years ago
Read 2 more answers
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