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grigory [225]
3 years ago
12

What is you’re typical approach to solving a math problem that looks too difficult or intimidating

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Answer:

People are more likely to avoid approaching difficult situations as they fear failure or looking bad to others if they get it wrong. They lack the point of view of being looked upon as brave for attempting something that others avoid.

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100 POINTS!!! ALGEBRA 1 PLEASE HELP!!! BRAINLIEST IF CORRECT
Ainat [17]

Answer:

<h2>1. (-6, 0) and (-1, 0)</h2><h2>2. not exist</h2><h2>3. (5, 0)</h2>

Step-by-step explanation:

The zeros of a quadratic function are x-intercepts of parabola.

Graph #1:

x = -6 and x = -1

Graph #2:

not exist

Graph #3:

x = 5

5 0
3 years ago
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The square of the binomial x-4 has the form x^2-ax+16. What is the value of a?
tia_tia [17]
A=-8x
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7 0
3 years ago
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Which relation is also a function?
slavikrds [6]

Answer:

Hi san, A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to. For example, consider the following sets X and Y.

This should help you a bit.

6 0
3 years ago
A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i
goldfiish [28.3K]

Answer:

  • P(t) = 100·2.3^t
  • 529 after 2 hours
  • 441 per hour, rate of growth at 2 hours
  • 5.5 hours to reach 10,000

Step-by-step explanation:

It often works well to write an exponential expression as ...

   value = (initial value)×(growth factor)^(t/(growth period))

(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...

  P(t) = 100·2.3^t

__

(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours

__

(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t

  P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour

__

(d) We want to find t such that ...

  P(t) = 10000

  100·2.3^t = 10000 . . . substitute for P(t)

  2.3^t = 100 . . . . . . . . divide by 100

  t·log(2.3) = log(100)

  t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000

6 0
4 years ago
Please help giving BRANLIEST to the best answer THIS SHOULD BE EASY
solniwko [45]

Answer:

the size difference of figure two to figure one gets smaller

Step-by-step explanation:

its kinda obvious

5 0
3 years ago
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