What is you’re typical approach to solving a math problem that looks too difficult or intimidating
1 answer:
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The phrase has two parts:
Five times the sum of a number and eleven, divided by three times the sum of the number and eight
Let the number be x. Five times the sum of a number and eleven means 5 multiplied to the sum of x and 11. In expression this will be written as:
5(x + 11)
Three times the sum of the number and eight means 3 multiplied to the sum of x and 8. In expression this will be written as:
3(x + 8)
So, the overall expression will be:
Five times the sum of a number and eleven, divided by three times the sum of the number and eight
Let the number be x. Five times the sum of a number and eleven means 5 multiplied to the sum of x and 11. In expression this will be written as:
5(x + 11)
Three times the sum of the number and eight means 3 multiplied to the sum of x and 8. In expression this will be written as:
3(x + 8)
So, the overall expression will be:
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
So the value of constant a is -5
Keywords: Polynomials, factorization
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