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grigory [225]
3 years ago
12

What is you’re typical approach to solving a math problem that looks too difficult or intimidating

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Answer:

People are more likely to avoid approaching difficult situations as they fear failure or looking bad to others if they get it wrong. They lack the point of view of being looked upon as brave for attempting something that others avoid.

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What is 3/4 + 1/2 and what is 1/3 + 11/48 in simplest form and a mixed number <br>​
alisha [4.7K]

Answer:

1) 5/4 or 1 1/4

2) 9/16

Step-by-step explanation:

3/4+1/2: you multiply 1/2 by 2 to get a common denominator then get 2/4, 3+2=5, 5/4 or 1 1/4

1/3+11/48: you multiply 1/3 by 16 to get common denominator & get 16/48, 16+11= 27/48, divide by 3 & get simplest form of 9/16

4 0
3 years ago
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The list below shows the ages of 10 visitors at a museum one morning.
brilliants [131]

Answer: A,

Step-by-step explanation: It makes a median of 28 when calculated

8 0
3 years ago
Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4

and solve for x'.

Hope that helps!
4 0
3 years ago
Emily kicked the ball in 1 straight direction , it went 10 ft reversed direction and come back to her , how is this possible ?
nydimaria [60]

Answer:

She kicked it up

Step-by-step explanation:

How is this math?

3 0
3 years ago
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Premier Bank is planning to have a new building constructed. They would like the length of the building to be 40 feet longer tha
MaRussiya [10]

Let L, W, F, H, P represent, respectively, the length, width, number of floors, height, and perimeter of the building. Here are some equations that model the given information.

  • L = W + 40
  • H = 12×F
  • foundation cost = 10×L×W
  • cost of floors = 35000×F
  • total cost = foundation cost + cost of floors
  • total cost = 1,180,000
  • P = 2×(L+W)
  • P = 3×H

We can rewrite these into a system of equations involving L, W, F.

Let's look first at the relation between the perimeter and height. The two versions of perimeter are equal to each other, so we have (after substituting for H) ...

... 3H = 2(L+W)

... 3(12F) = 2((W +40) +W) . . . . substitute for H and L

... 36F = 4W +80 . . . . . . . . . . . simplify

... 9F = W +20 . . . . . . . . . . . . . divide by 4

Now, we can look at the cost equations.

... 1180000 = 35000F + 10W(W+40) . . . . . substitute for the various cost terms and for L

... 118000 = 3500F +W² +40W . . . . . . . . . divide by 10

The two simplified equations in W and F are ...

  • 9F = W +20
  • 3500F = 118000 -40W -W²

You can solve the first for F and substitute for F in the second. Then you have a quadratic equation in W that can be solved by the usual methods. (Likely, the quadratic formula would be the best choice.) Here, we have elected to let a graphing calculator show the two solutions. One solution has negative dimensions, so is clearly infeasible.

There is one (nearly feasible) solution:

... W ≈ 180.788

... F ≈ 22.31

There is no combination of floor dimensions and integral numbers of floors that will match <em>all</em> of the problem requirements.

_____

A solution that comes about as close as possible is ...

  • length = 221 ft
  • width = 181 ft
  • perimeter = 804 ft
  • # of floors = 22
  • height = 264 ft . . . . . (3×height = 792 ft vs. 804 ft)
  • cost = $1,170,010 . . . (vs. 1,180,000)

4 0
3 years ago
Read 2 more answers
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