Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
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b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
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The attached graphs show these to be plausible values for the derivatives at the given points.
Answer:
3.8 = 38/10
Step-by-step explanation:
The given number = 3.8
We have to write 3.8 in fraction form a/b
Here we have 1 digit after the decimal. To get rid off the decimal number, we need to multiply both the numerator and the denominator by 10 since we have to 1 digit after the decimal.
= 38/10
Therefore, the answer is 3.8 = 38/10
Thank you.
To solve this problem, we need to use the midpoint formula, where M = (x1+x2/2, y1+y2/2). To solve, we must plug in the given (x,y) values from our ordered pairs and then simplify, shown below:
(x1+x2/2, y1+y2/2)
( (16 + -6)/2, (5 + -9)/2 )
Now, we can begin to simplify by computing the addition in the numerators of both fractions.
(10/2, -4/2)
Next, we can finish the simplification process by dividing these fractions.
(5, -2)
Therefore, the midpoint of (16,5) and (-6,-9) is (5,-2).
Hope this helps!
Answer:
8
Step-by-step explanation:
goes plus 1 then plus 2 then plus 3 so then it would be plus 4
