First we have to get x by itself, so we multiply two on each side,
then we get 5x=660/4, I like to simplify here, so I would change it to 5x=165, then we divide each side by 5
x=33
:)
Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
A. 6c
B. -5c
C. -0.7c
D. 2c
Just a few you could use.
Answer:
Step-by-step explanation:
We have to first find the vertices of the feasible region before we can determine the max value of P(x, y). We will graph all 4 of those inequalities in a coordinate plane and when we do that we find that the region of feasibility is bordered by the vertices (0, 0), (0, 1), (2, 3), and (5, 0). Filling each x and y value into our function will give us the max value of that function.
Obviously, when we sub in (0, 0). we get that P(x, y) = 0.
When we sub in (0, 1) we get 24(0) + 30(1) = 30.
When we sub in (2, 3) we get 24(2) + 30(3) = 138.
When we sub in (5, 0) we get 24(5) + 30(0) = 120.
Obviously, the vertex of (2, 3) maximized our function for a value of 138.
Answer:
x= 16
Step-by-step explanation:
First, you want to distribute each side! (you're gonna wanna learn this because you will be having to do it for the next 3 years no joke it sucks)
7(x+2) can be distributed as 7x+14 after multiplying 7 times x and 7 times 2, and 6(x+5) can be distributed as 6x+30.
Now, you have to get the x on one side to solve for x (so like x=__).
To do this, look at the equation as of now. 7x+14=6x+30.
We can minus 14 and bring that to the right, and minus 6x and bring that to the left to separate the x's and the regular numbers.
Now we have 16=x (or x=16).
