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nadya68 [22]
3 years ago
7

Diego and Lin are drinking milkshakes. Lin starts with 12 ounces and drinks 1/4 an ounce per second. Diego starts with 20 ounces

and drinks 2/3 an ounce per second. 1. How long will it take Lin and Diego to finish their milkshakes?
Mathematics
1 answer:
sammy [17]3 years ago
3 0

Answer:

Lin = 48 seconds  

Diego = 30 seconds  

Step-by-step explanation:

Hi, to answer this question we have to divide the total ounces of drink by the amount that each one drank per second, for each case.

Mathematically speaking:

Lin = 12 ounces / (1/4) ounces/second = 12/ (1/4) = 48 seconds  

Diego = 20 ounces / (2/3) ounces/second = 20/ (2/3) = 30 seconds  

Feel free to ask for more if needed or if you did not understand something.

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3q + 2 (q + 1)               :Distribute

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<em><u>5q + 1</u></em>
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The total of a number divided by nine and eleven is four
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3 0
3 years ago
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1863 mailboxes t
forsale [732]

Answer:

3433 m²

Step-by-step explanation:

From the image, we have a rectangular box without cover and half a cylinder on top.

Formula for surface area of rectangular box with top is;

S = 2(lh + wh + lw)

From the image,

l = 0.6 m

w = 0.4 m

h = 0.55 m

Thus;

S = 2((0.6 × 0.55) + (0.4 × 0.55) + (0.6 × 0.4))

S = 1.58 m²

Now, since the top is not included for this figure, then;

Surface area of this rectangular box is;

S1 = 1.58 - (lw) = 1.58 - (0.4 × 0.6) = 1.34 m²

Surface area of a cylinder is;

S = 2πr² + 2πrh

r is radius and in this case = 0.4/2 = 0.2 m

h = 0.6

S = 2π(0.2² + (0.2 × 0.6))

S = 1.005 m²

Since it is half cylinder, then we have;

S2 = 1.005/2

S2 = 0.5025 m²

Total surface area; S_t = S1 + S2

S_t = 1.34 + 0.5025

S_t = 1.8425 m²

This is the surface area of one mail box.

Thus, for 1863 mailboxes, total surface area is;

S = 1863 × 1.8425 = 3432.5775 m²

Approximating to the nearest Sq.m gives;

S = 3433 m²

6 0
3 years ago
Geometry help help help
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8 0
3 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
2 years ago
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