Answer:
A) (-9/7,0), (3/8,0)
Step-by-step explanation:
Zeros of a quadratic function:
x for which y = 0.
In this question:

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:



So (-9/7, 0) is a zero of the quadratic function.
The other is:



(3/8,0) is the other zero.
Thus, the correct answer is given by option A.
Answer:
Option C .
Step-by-step explanation:
We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>


Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>



Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>



<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>
The remainder is always less than the divisor because if the remainder was more than the divisor then you would have a totally different answer. If the remainder was more than the divisor than you know your answers wrong.
It would be 16.5 inches long.
First you have to divide 11 by 8 (1.375) to get how long would the letter be if it was 1 inch wide. Then multiply 1.375 by 12 which is 16.5.
Answer:
The total number of students in the school is 750. You can use algebraic equation to calculate the number of the students. Let x be the total number of students in the school. Hope this helps.