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hjlf
3 years ago
8

Part 1: Create an equation of a line in point-slope form. Be sure to identify all parts of the equation before writing the equat

ion.
Part 2: Using the equation of the line you wrote in part 1, write an equation of a line that is perpendicular to this line.
Mathematics
2 answers:
mixer [17]3 years ago
5 0

Covers the 'point-slope' form of linear equations, including how to find a line ... For this one, they give you a point (x1, y1) and a slope m, and have you plug it into this ... You can use the Mat way widget below to practice finding a line equation .... Find the equation of the line that passes through the points (–2, 4) and (1, 2)

harina [27]3 years ago
5 0
<h2>Answer with explanation:</h2>

<u>Part--1:</u>

We know that a equation in point-slope form is represented by:

               y-y_1=m(x-x_1)

where m is the slope of the line and (x_,y_1) is a point through which the line passes.  

  Consider a equation in a point-slope form as:

           y-5=2(x-1)

This means that the slope of the line is: 5

and the line  passes through the point (1,5).

<u>Part--2:</u>

Now as we know that if a line has a slope as m then the perpendicular line has a slope: -1/m

Since,

m\times \text{Slope\ of\ second\ line}=-1\\\\i.e.\\\\\text{Slope\ of\ second\ line}=\dfrac{-1}{m}

Let this perpendicular line passes through (2,6)

Hence, the equation of a line in point slope form is given by:

             y-6=\dfrac{-1}{2}(x-2)

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Answer:

x=81\degree

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z=129\degree

Step-by-step explanation:

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The exterior angle y is the sum of the two remote interior angles:

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2 years ago
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bearing in mind that standard form for a linear equation means

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\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-(-9)}{10-9}\implies \cfrac{-5+9}{1}\implies \cfrac{4}{1}\implies 4

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-9)=4(x-9)\implies\underline{y+9=4(x-9)} \\\\\\ y+9=4x-36\implies y=4x-45\implies \stackrel{standard~form}{\underline{-4x+y=-45}}

quick note:

the "x" must not have a negative coefficient for the standard form, though in this case it shows like so in the inappropriate choices above.

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