All categories

3 years ago

HELP PLEASE!!!!!!!!!

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

Answer:

The answer in one common tangent only ⇒ answer (B)

Step-by-step explanation:

∵ The two circles touch internally in a common point

* At this point we can draw only one tangent

∵ This point is common in the two circles

∴ The tangent will be common for the two circles

∴ There is only one common tangent can be draw passing

through the common point which the two circles

touch each other on it

∴ The answer is (B)

You might be interested in

The figure below shows a line graph and two shaded triangles that are similar:

VLD [36.1K]

Every time the y-value decreases by 1, the x-value increases by 2, so the slope is -1/2 throughout the line.

4 0

3 years ago

Read 2 more answers

Solve the area formula for h

White raven [17]

The answer is C: $h = \frac{2A}{b}$

Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is $\frac{1}{b}$ on both sides of the equation:

$A(\frac{1}{b}) = \frac{1}{2}hb* (\frac{1}{b})$

The result will be:

$\frac{A}{b} = \frac{1}{2}h$

The last step is to use the multiplicative inverse of $\frac{1}{2}$ , which is 2 or $\frac{2}{1}$ to further isolate the variable h :

$\frac{A}{b} (\frac{2}{1}) = (\frac{2}{1}) \frac{1}{2} h$

The formula for h will be:

$h = \frac{2A}{b}$ which is the option C in your question.

4 0

3 years ago

U need to find out 3/4 divided by what = 3/24

vivado [14]

.16i belive is your answer

7 0

3 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

3 years ago

Anyone good at maths who can help me? brainiest will be given, THANK YOU!!!

pentagon [3]

Answer:

a) £338.64 b) 21.73kg c) 334.65m

Step-by-step explanation:

on calculator type:

408x83%

53x41%

345x97%

4 0

3 years ago

Read 2 more answers