The best way, in my opinion, to do this, is to find the unit rate of each napkin brand, or the cost per napkin. To do this, divide the money amount by the amount of napkin they give you.
/Brand W:2.87/500=.00574 \
\Brand X: 1.27/200=.00635 \ These are the
/Brand Y: .62/100 =.0062 / cost per napkin.
\Brand Z: 1.37/250=.00548 /
Which one out of these 4 values is the lowest value? Obviously the two with the 6 in the thousandths place are more expensive than the ones with the 5s in the thousandths place, so that already eliminates Brand Z and Brand W.
What do we have left?
<span>Brand X: 1.27/200=.00635
</span><span>Brand Y: .62/100 =.0062
</span> Cool. Which of these is a smaller number? Tip: If the first number besides 0 is the same, check the next one! You should get that Brand Y is the cheapest! :) Hoped this helped!
Answer:
0
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Step-by-step explanation:
give brainliest or vanish
Answer:
Domain: (-∞, ∞)
Range: (0,∞)
Step-by-step explanation:
Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.
However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.
The addition to 1 on the exponent shifts the function to the left but doesn't change the range.
In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).
Domain: (-∞, ∞)
Range: (0,∞)
Answer:
The number of questions in sixth assignment must be less than or equal to 28.
Step-by-step explanation:
The number of questions in first five assignments are 11,10,13,14 and 14.
It is given that Mrs hawk assigns her students an average of no more than 15 questions on each assignment. Therefore the average of six assignments is less than or equal to 15 questions.
Let the number of questions in sixth assignment be x

Average of six assignments are


Since the average of questions is no more than 15, therefore




Therefore the number of questions in sixth assignment must be less than or equal to 28.
Answer:
C
Step-by-step explanation:
Process of elimination