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EleoNora [17]
4 years ago
5

Y-1=2/3(x-5) in standard form

Mathematics
2 answers:
AURORKA [14]4 years ago
8 0

y - 1 =  \frac{2}{3} (x - 5)
y -  \frac{3}{3} =  \frac{2}{ 3} x - \frac{10}{3}
y =  \frac{2}{3} x -  \frac{7}{3}
Therefore
\frac{2x}{3}  - y =  \frac{7}{3}
Since ax+by=c is standard form
Reptile [31]4 years ago
5 0
The answer would be 2x/3 -y = 7/3
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I believe its 57.

Step-by-step explanation:

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Please help me with this question
oksano4ka [1.4K]

Answer: 5, 3, \dfrac{1}{6}, D

<u>Step-by-step explanation:</u>

-5 < 0 so f(-5) = | -5 | = 5

-3 < 0 so f(-3) = | -3 | = 3

6 > 0 so f(6) = \dfrac{1}{6}

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3 years ago
If y varies jointly with x and z and y=40 when x=10 and z=9 find z when x =55 and y=105
Eduardwww [97]

Answer:

  z = 189/44

Step-by-step explanation:

The "varies jointly" relationship can be expressed by ...

  y = kxz

We can find k from the given values.

  40 = k(10)(9)

  40/90 = k = 4/9 . . . divide by the coefficient of k

Now we want to find z for given values of x and y. That can be found from ...

  y = (4/9)xz

  9y/(4x) = z . . . . . multiply by 9/(4x)

Filling in the new numbers, we have ...

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4 years ago
1
luda_lava [24]

Answer:

See the solution

Step-by-step explanation:

4 0
3 years ago
Simplify the following: <br><br> 3to the power of 2 x 3 to the power of 2??
Veseljchak [2.6K]
<h2>Correct question;</h2>

<h2>3 {}^{2}  \times 3 {}^{2}</h2><h2>Required solution;</h2>

<h3>↠ Multiply the terms with the same base by adding their exponents</h3>

<h2>3 {}^{2 + 2}</h2><h3>↠ Add the numbers</h3>

<h2>3 {}^{4}</h2>
  • You can also expand it

After expanding the answer will be 81

expanded \: form \:  = 3 \times 3 \times 3 \times 3 = 81

Hope it helps...

《I own the rights of this answer》

6 0
3 years ago
Read 2 more answers
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