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bazaltina [42]
3 years ago
7

Find the output, g, when the input, r, is 3. g = -5r+13 g=_____

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

g = -2

Step-by-step explanation:

g = -5r + 13

r = 3

You substitute three for r in the equation.

--------------------------------------------------------------

g = -5(3) + 13

--------------------------------------------------------------

Distribute -5 to 3

--------------------------------------------------------------

g = -15 + 13

--------------------------------------------------------------

Solve

-------------------------------------------------------------

g = -15 + 13

-15 + 13 = -2

g = -2

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in 2010, the price of a laser printer was $1599. in 2018, the price of the same type of printer had dropped to $579. find the pe
uysha [10]

Hi there!

nearest percentage=64%

<em><u>1.Subtract starting value and final value:</u></em>

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<em><u /></em>1020*1599= 0.6378986866791744840525328330206378986<em><u /></em>

<em><u>3.Multiply the term by 100:</u></em>

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Therefore, the decrease of the total 8 years was 64%.

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3 years ago
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Pratctice and Solving Solve each equation with variables on both sides 1. 6x - 2 = x + 13​
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Answer:

x=3

Step-by-step explanation:

6x - 2 = x + 13

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3 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
3 years ago
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