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3 years ago

Can anyone please help me?

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer:

f(0)

Step-by-step explanation:

The y intersect and x intercept are both 0 so you get f(0)

Hope this helps

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3x^2y^3+5x^3y^3-6+x^3y^2-2

klasskru [66]

3x^2y^3+5x^3y^3-6+x^3y^2-2
= (3x^2y^3+5x^3y^3+x^3y^2)-(6+2)
= x^2y^2(3y+5xy+x)-8.

The final answer is x^2y^2(3y+5xy+x)-8~

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3 years ago

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VMariaS [17]

Please look at the pic below hope it helps.

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3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago

I thought of a number, added 4 5/7 to it, and got the number 12 times as big as my original what was my number

Genrish500 [490]

Let's call the number you thought of n. Then what the two steps you took can be written as an equation:
$n+4\frac{5}{7}=12n$

Subtract n to get all of your variables to one side:
$4\frac{5}{7}=11n$

At this point, I recommend turning your mixed number into an improper fraction. It will make things easier later on:
$\frac{33}{7}=11n$

Now divide both sides by 11 to get the value of n:
$\frac{3}{7}=n$

7 0

3 years ago

Read 2 more answers

What is 7 more than five times the number 9 divided by 15??

katrin2010 [14]

the answer is 10. 5 times 9 = 45 and it says 45 divided by 15 which is 3 and it says seven more than 9 divided by 15 so 10 bb :)

8 0

3 years ago