Answer:
the slope is -4/5 and the y-intercept is 0
Step-by-step explanation:
She done better at the 2nd test because she only got 4 wrong but on the first test she got 6 wrong.
Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1)
Finally, using distributive property and foil, you would get x^2+x+x^2-3x+2=(-x^2+x+2).2x^2-2x+2=-x^2+x+23x^2-3x=0
3x(x-1)x=0 and x=1
Answer:
x=11
Step-by-step explanation:
The switch case works like an if or if-else, where each of the cases are conditionals. Here we have 7 cases and we know that our variable begins with x=5.
First, it enters to case 5 because of x=5, so x+=3, this means we add 3 to the actual value of the variable ⇒ x=8.
At this point, if there's not break the program continues to the next case, executing the statements until a break or the end on the switch is reached.
In this order, the x = 8 and next we add 1 (case 6) ⇒ x=9. We add 2 (case 7) x+=2 ⇒ x=10. Then we rest 1 (case 8) ⇒ x=9 and then we add 1 again as in case 9 ⇒ x=11.
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
