<span>The answer is (x</span>¹⁰<span>y</span>¹⁴<span>)/729.
Explanation:
We can begin simplifying inside the innermost parentheses using the properties of exponents. The power of a power property says when you raise a power to a power, you multiply the exponents. This gives us
[(3</span>³<span>x</span>³<span>y</span>⁻¹⁵<span>)/(x</span>⁸<span>y</span>⁻⁸<span>)]</span>⁻²<span>.
Negative exponents tell us to "flip" sides of the fraction, so within the parentheses we have
[(3</span>³<span>x</span>³<span>y</span>⁸<span>)/(x</span>⁸<span>y</span>¹⁵<span>)]</span>⁻²<span>.
Using the quotient property, we subtract exponents when dividing powers, which gives us
(3</span>³<span>/x</span>⁵<span>y</span>⁷<span>)</span>⁻²<span>.
Evaluating 3</span>³<span>, we have
(27/x</span>⁵<span>y</span>⁷<span>)</span>⁻²<span>.
Using the power of a power property again, we have
27</span>⁻²<span>/x</span>⁻¹⁰<span>y</span>⁻¹⁴<span>.
Flipping the negative exponents again gives us x</span>¹⁰<span>y</span>¹⁴<span>/729.</span>
Answer:
a+4=
Step-by-step explanation:
Answer:
on what? I will, but on what?
Answer:
The value of x is 
.
Step-by-step explanation:
Please look at the figure attached to get more clear solution.
We have given:
FG||CB
And the line that cut the parallel line is transversal so, here BA is transversal
And alternate interior angles on transverse line are equal
So, ∠1=∠4
And ∠4=
Hence, ∠1=∠4=
And On FG the sum of angles will be 
∠3+∠2+∠1=
+∠2+=
Hence, ∠2=
Now, we know that the sum of interior angles is equal to the exterior angle:
Therefore, ∠2+∠5=∠6+∠7
On simplification we get:
Hence, the value of x is .
Answer:
- proportional: A, B, D, G, I
- non-proportional: C, E, F, H
Step-by-step explanation:
Any relation with a non-zero initial value or y-intercept is non-proportional. Any relation that has a constant ratio between output and input is proportional.
C has an initial value of 7
E has a y-intercept of -3
F has an initial value of 2.00
H has an initial value of 5
All of these are non-proportional. The remainder are proportional.
