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Rudik [331]
3 years ago
12

helene is selling cupcakes for $0.50 each. The function f(x)=0.5x gives the total amount of money here makes after selling x cup

cakes. graph this function and give its domain and range.
Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:

P(x) = 1.75x - 0.5

Step-by-step explanation:

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ra1l [238]

Answer:   5  1/2

Step-by-step explanation:

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Quadrilateral DUCKDUCKD, U, C, K is inscribed in circle OOO. What is the measure of \angle K∠Kangle, K?
N76 [4]

Answer:

Measure of ∠K=180-∠U

Or

Measure of ∠K=1/2m(arc DUC)

Step-by-step explanation:

Given:

DUCK quadrilateral inscribed in circle with center O

To Find:

Measure angle K

Solution:

Here the Quadrilateral in inscribed in a circle with center O named as DUCK

So angle K and  U are opposite to each other

We know that the angle of Quadrilateral inscribed in a circle are supplemenatry angles

Hence

∠U+∠K=180

Or The ∠K=1/2*m∠arc(DUC).

Hence depending on the given value for arc measure or angle of quadrilateral we calculate the angle K

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3 years ago
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REY [17]

Answer:

84

Step-by-step explanation:

they are all equal sides so what you'd do is 28+28+28= 84

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3 years ago
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A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height
melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

x\geq 0

The height of the food packet cannot be a negative value, so

f(x)\geq 0

We need to replace -15x^2+6000 for f(x) in the above inequality to find the domain.

-15x^2+6000\geq 0 \; \;  [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0

The possible solutions of the above inequality are given by the intervals (-\infty , -2], [-2,2], [2,\infty ). We need to pick test point from each possible solution interval and check whether that test point make the inequality (x+200)(x-200)\leq 0 true. Only the test point from the solution interval [-200, 200] make the inequality true.

The values of x which will make the above inequality TRUE is -200\leq x\leq 200

But we already know x should be positive, because time cannot be negative.

Conclusion:

Domain of the given function is 0\leq x\leq 200

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Zigmanuir [339]

Answer:

(2 , 30)   & (4, 60)

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